Factorise : $2 x^{2}+7 x+3$
Factorise : $2 x^{2}+7 x+3$
$2 x^{2}+7 x+3$
Here, $a =2,\, b =7$ and $c =3$
$\therefore \quad l+ m =7$ and $lm =2 \times 3=6$ i.e. $1+6=7$ and $1 \times 6=6$
$ \therefore $ $l=1$ and $m =6$
We have $ 2 x ^{2}+7 x +3=2 x ^{2}+x +6 x +3 $
$= x (2 x +1)+3(2 x +1)=(2 x +1)( x +3) $
Thus, $\quad 2 x^{2}+7 x+3=(2 x+1)(x+3)$
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